Quantcast
Channel: 婚活キューピッド
Viewing all articles
Browse latest Browse all 100

Answer by Chakravarthy Kalyan for Which is more basic: 1,2‐dihydropyridine or 1,4‐dihydropyridine?

$
0
0

In compound $\ce{A}$ , lone pair on $\ce{N}$ is in conjugation with two $\ce pi$ bonds (as shown below). Therefore this lone pair is delocalized (resonance structures in the figure below) to a greater extent.

In compound $\ce{B}$ , lone pair on $\ce{N}$ is in conjugation with a single $\ce pi$ bond , while the other pi bond is not in conjugation or is cross conjugated.

Since lone pair on $\ce{N}$ in compound $\ce{B}$ is less delocalized then in compound $\ce{A}$ , compound $\ce{B}$ is more basic then compound $\ce{A}$.

enter image description here


Viewing all articles
Browse latest Browse all 100

Trending Articles



<script src="https://jsc.adskeeper.com/r/s/rssing.com.1596347.js" async> </script>